Which statement about the relationship between hazard rate, FIT, and MTBF is true under a constant hazard assumption?

Study for the TSG Reliability Exam. Prepare with flashcards and multiple choice questions, each question includes hints and explanations. Ready to succeed!

Multiple Choice

Which statement about the relationship between hazard rate, FIT, and MTBF is true under a constant hazard assumption?

Explanation:
With a constant hazard rate, the time to failure follows an exponential distribution, so the mean time between failures (MTBF) is the reciprocal of the hazard rate. The hazard rate λ is the instantaneous failure rate per hour, and for an exponential model the expected time to failure is E[T] = 1/λ, which is the MTBF. FIT (Failures In Time) is a rate expressed as failures per 10^9 hours. Therefore FIT = λ × 10^9. Substituting λ = 1/MTBF gives FIT = 10^9 / MTBF, or equivalently MTBF = 10^9 / FIT. This is why the statement MTBF equals the reciprocal of the hazard rate is the correct relation under a constant hazard.

With a constant hazard rate, the time to failure follows an exponential distribution, so the mean time between failures (MTBF) is the reciprocal of the hazard rate. The hazard rate λ is the instantaneous failure rate per hour, and for an exponential model the expected time to failure is E[T] = 1/λ, which is the MTBF.

FIT (Failures In Time) is a rate expressed as failures per 10^9 hours. Therefore FIT = λ × 10^9. Substituting λ = 1/MTBF gives FIT = 10^9 / MTBF, or equivalently MTBF = 10^9 / FIT.

This is why the statement MTBF equals the reciprocal of the hazard rate is the correct relation under a constant hazard.

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